Base | Representation |
---|---|
bin | 11101101000010011101001… |
… | …110010111110000000000000 |
3 | 122002101211020001220210000021 |
4 | 131220103221302332000000 |
5 | 114040022443413304440 |
6 | 1141053023240303224 |
7 | 36306551216453053 |
oct | 3550235162760000 |
9 | 562354201823007 |
10 | 130313230213120 |
11 | 38581592218459 |
12 | 127476b1171b14 |
13 | 579363c38aa66 |
14 | 24272a0474a9a |
15 | 100eb2d4d084a |
hex | 7684e9cbe000 |
130313230213120 has 224 divisors, whose sum is σ = 322961982610176. Its totient is φ = 50421773107200.
The previous prime is 130313230213099. The next prime is 130313230213123. The reversal of 130313230213120 is 21312032313031.
It is a super-2 number, since 2×1303132302131202 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130313230213123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3068988690 + ... + 3069031150.
It is an arithmetic number, because the mean of its divisors is an integer number (1441794565224).
Almost surely, 2130313230213120 is an apocalyptic number.
130313230213120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130313230213120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161480991305088).
130313230213120 is an abundant number, since it is smaller than the sum of its proper divisors (192648752397056).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130313230213120 is an equidigital number, since it uses as much as digits as its factorization.
130313230213120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44940 (or 44916 counting only the distinct ones).
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 130313230213120 its reverse (21312032313031), we get a palindrome (151625262526151).
The spelling of 130313230213120 in words is "one hundred thirty trillion, three hundred thirteen billion, two hundred thirty million, two hundred thirteen thousand, one hundred twenty".
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