Base | Representation |
---|---|
bin | 11000010001011101… |
… | …00110010110000101 |
3 | 1020122011202102102012 |
4 | 30020232212112011 |
5 | 203142010212201 |
6 | 5553030424005 |
7 | 640633344125 |
oct | 141056462605 |
9 | 36564672365 |
10 | 13031335301 |
11 | 55879380a6 |
12 | 2638202005 |
13 | 12c8a236ba |
14 | 8b89a4c85 |
15 | 5140915bb |
hex | 308ba6585 |
13031335301 has 2 divisors, whose sum is σ = 13031335302. Its totient is φ = 13031335300.
The previous prime is 13031335211. The next prime is 13031335321. The reversal of 13031335301 is 10353313031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 6951390625 + 6079944676 = 83375^2 + 77974^2 .
It is an emirp because it is prime and its reverse (10353313031) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13031335301 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13031335321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515667650 + 6515667651.
It is an arithmetic number, because the mean of its divisors is an integer number (6515667651).
Almost surely, 213031335301 is an apocalyptic number.
It is an amenable number.
13031335301 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031335301 is an equidigital number, since it uses as much as digits as its factorization.
13031335301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1215, while the sum is 23.
Adding to 13031335301 its reverse (10353313031), we get a palindrome (23384648332).
The spelling of 13031335301 in words is "thirteen billion, thirty-one million, three hundred thirty-five thousand, three hundred one".
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