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130314234111214 = 2471386321639481
BaseRepresentation
bin11101101000010100100101…
…101000100010010011101110
3122002101220211000221002022011
4131220110211220202103232
5114040032022413024324
61141053311021311434
736306615126450466
oct3550244550422356
9562356730832264
10130314234111214
1138581a579639aa
121274793140557a
13579376c3612ba
142427357918ba6
15100eb8b6d1c94
hex768525a224ee

130314234111214 has 8 divisors (see below), whose sum is σ = 199630316085408. Its totient is φ = 63770795416080.

The previous prime is 130314234111179. The next prime is 130314234111233. The reversal of 130314234111214 is 412111432413031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×1303142341112142 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 693160819647 + ... + 693160819834.

It is an arithmetic number, because the mean of its divisors is an integer number (24953789510676).

Almost surely, 2130314234111214 is an apocalyptic number.

130314234111214 is a deficient number, since it is larger than the sum of its proper divisors (69316081974194).

130314234111214 is a wasteful number, since it uses less digits than its factorization.

130314234111214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1386321639530.

The product of its (nonzero) digits is 6912, while the sum is 31.

Adding to 130314234111214 its reverse (412111432413031), we get a palindrome (542425666524245).

The spelling of 130314234111214 in words is "one hundred thirty trillion, three hundred fourteen billion, two hundred thirty-four million, one hundred eleven thousand, two hundred fourteen".

Divisors: 1 2 47 94 1386321639481 2772643278962 65157117055607 130314234111214