Base | Representation |
---|---|
bin | 11000010001011110… |
… | …11110100001111001 |
3 | 1020122012012010002121 |
4 | 30020233132201321 |
5 | 203142040043213 |
6 | 5553035401241 |
7 | 640635323065 |
oct | 141057364171 |
9 | 36565163077 |
10 | 13031565433 |
11 | 5587a84a97 |
12 | 26382b3221 |
13 | 12c8aa4383 |
14 | 8b8a24aa5 |
15 | 5140d988d |
hex | 308bde879 |
13031565433 has 2 divisors, whose sum is σ = 13031565434. Its totient is φ = 13031565432.
The previous prime is 13031565409. The next prime is 13031565439. The reversal of 13031565433 is 33456513031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12527877184 + 503688249 = 111928^2 + 22443^2 .
It is an emirp because it is prime and its reverse (33456513031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13031565433 - 25 = 13031565401 is a prime.
It is not a weakly prime, because it can be changed into another prime (13031565439) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6515782716 + 6515782717.
It is an arithmetic number, because the mean of its divisors is an integer number (6515782717).
Almost surely, 213031565433 is an apocalyptic number.
It is an amenable number.
13031565433 is a deficient number, since it is larger than the sum of its proper divisors (1).
13031565433 is an equidigital number, since it uses as much as digits as its factorization.
13031565433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48600, while the sum is 34.
The spelling of 13031565433 in words is "thirteen billion, thirty-one million, five hundred sixty-five thousand, four hundred thirty-three".
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