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13032000121589 is a prime number
BaseRepresentation
bin1011110110100011111110…
…1111001110101011110101
31201010211212111101010122222
42331220333233032223311
53202004014012342324
643414452422132125
72513350053216461
oct275507757165365
951124774333588
1013032000121589
114174927363779
121565832581045
13736bb253acc7
14330a75d5b4a1
15178ed3b9955e
hexbda3fbceaf5

13032000121589 has 2 divisors, whose sum is σ = 13032000121590. Its totient is φ = 13032000121588.

The previous prime is 13032000121561. The next prime is 13032000121627. The reversal of 13032000121589 is 98512100023031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9475222894225 + 3556777227364 = 3078185^2 + 1885942^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13032000121589 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13032000121559) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516000060794 + 6516000060795.

It is an arithmetic number, because the mean of its divisors is an integer number (6516000060795).

Almost surely, 213032000121589 is an apocalyptic number.

It is an amenable number.

13032000121589 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032000121589 is an equidigital number, since it uses as much as digits as its factorization.

13032000121589 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12960, while the sum is 35.

The spelling of 13032000121589 in words is "thirteen trillion, thirty-two billion, one hundred twenty-one thousand, five hundred eighty-nine".