Base | Representation |
---|---|
bin | 1011110110100100000001… |
… | …0101000000000110010000 |
3 | 1201010211220012000012021110 |
4 | 2331221000111000012100 |
5 | 3202004024031221222 |
6 | 43414453414253320 |
7 | 2513350233326460 |
oct | 275510025000620 |
9 | 51124805005243 |
10 | 13032010023312 |
11 | 4174931a07015 |
12 | 1565835957240 |
13 | 736bb45c6c07 |
14 | 330a773b7ba0 |
15 | 178ed49a330c |
hex | bda40540190 |
13032010023312 has 80 divisors (see below), whose sum is σ = 38617434294272. Its totient is φ = 3709691809920.
The previous prime is 13032010023299. The next prime is 13032010023343. The reversal of 13032010023312 is 21332001023031.
It is a super-3 number, since 3×130320100233123 (a number of 40 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 71469358 + ... + 71651469.
Almost surely, 213032010023312 is an apocalyptic number.
13032010023312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
13032010023312 is an abundant number, since it is smaller than the sum of its proper divisors (25585424270960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13032010023312 is a wasteful number, since it uses less digits than its factorization.
13032010023312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 143121116 (or 143121110 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 13032010023312 its reverse (21332001023031), we get a palindrome (34364011046343).
The spelling of 13032010023312 in words is "thirteen trillion, thirty-two billion, ten million, twenty-three thousand, three hundred twelve".
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