Base | Representation |
---|---|
bin | 1011110110100100000001… |
… | …1000110100101011010011 |
3 | 1201010211220020220002110222 |
4 | 2331221000120310223103 |
5 | 3202004024310300412 |
6 | 43414453451543255 |
7 | 2513350245001244 |
oct | 275510030645323 |
9 | 51124806802428 |
10 | 13032011025107 |
11 | 4174932530748 |
12 | 156583615ab2b |
13 | 736bb4887ba9 |
14 | 330a77598ccb |
15 | 178ed4b00072 |
hex | bda40634ad3 |
13032011025107 has 2 divisors, whose sum is σ = 13032011025108. Its totient is φ = 13032011025106.
The previous prime is 13032011025083. The next prime is 13032011025119. The reversal of 13032011025107 is 70152011023031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13032011025107 - 26 = 13032011025043 is a prime.
It is a super-2 number, since 2×130320110251072 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13032011025197) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516005512553 + 6516005512554.
It is an arithmetic number, because the mean of its divisors is an integer number (6516005512554).
Almost surely, 213032011025107 is an apocalyptic number.
13032011025107 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032011025107 is an equidigital number, since it uses as much as digits as its factorization.
13032011025107 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1260, while the sum is 26.
Adding to 13032011025107 its reverse (70152011023031), we get a palindrome (83184022048138).
The spelling of 13032011025107 in words is "thirteen trillion, thirty-two billion, eleven million, twenty-five thousand, one hundred seven".
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