13032011025119 has 2 divisors, whose sum is σ = 13032011025120. Its totient is φ = 13032011025118.

The previous prime is 13032011025107. The next prime is 13032011025191. The reversal of 13032011025119 is 91152011023031.

Together with next prime (13032011025191) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13032011025119 is a prime.

It is a super-2 number, since 2×13032011025119² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13032011025091 and 13032011025100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13032011025619) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516005512559 + 6516005512560.

It is an arithmetic number, because the mean of its divisors is an integer number (6516005512560).

Almost surely, 2^{13032011025119} is an apocalyptic number.

13032011025119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032011025119 is an equidigital number, since it uses as much as digits as its factorization.

13032011025119 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 29.

The spelling of 13032011025119 in words is "thirteen trillion, thirty-two billion, eleven million, twenty-five thousand, one hundred nineteen".