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13032011033381 is a prime number
BaseRepresentation
bin1011110110100100000001…
…1000110110101100100101
31201010211220020220111211102
42331221000120312230211
53202004024311032011
643414453452045445
72513350245034334
oct275510030665445
951124806814742
1013032011033381
11417493253698a
121565836163885
13736bb488b8a2
14330a7759bd1b
15178ed4b0273b
hexbda40636b25

13032011033381 has 2 divisors, whose sum is σ = 13032011033382. Its totient is φ = 13032011033380.

The previous prime is 13032011033267. The next prime is 13032011033417. The reversal of 13032011033381 is 18333011023031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9232688869156 + 3799322164225 = 3038534^2 + 1949185^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032011033381 - 230 = 13030937291557 is a prime.

It is a super-2 number, since 2×130320110333812 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13032013033381) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516005516690 + 6516005516691.

It is an arithmetic number, because the mean of its divisors is an integer number (6516005516691).

Almost surely, 213032011033381 is an apocalyptic number.

It is an amenable number.

13032011033381 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032011033381 is an equidigital number, since it uses as much as digits as its factorization.

13032011033381 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 29.

The spelling of 13032011033381 in words is "thirteen trillion, thirty-two billion, eleven million, thirty-three thousand, three hundred eighty-one".