Base | Representation |
---|---|
bin | 1011110110100100000100… |
… | …0110100000111111101001 |
3 | 1201010211221002102122012211 |
4 | 2331221001012200333221 |
5 | 3202004040342044423 |
6 | 43414455000405121 |
7 | 2513350451546452 |
oct | 275510106407751 |
9 | 51124832378184 |
10 | 13032023003113 |
11 | 4174939271a24 |
12 | 156583a1767a1 |
13 | 736bb71bcb7a |
14 | 330a78dd6129 |
15 | 178ed5bb910d |
hex | bda411a0fe9 |
13032023003113 has 2 divisors, whose sum is σ = 13032023003114. Its totient is φ = 13032023003112.
The previous prime is 13032023003081. The next prime is 13032023003183. The reversal of 13032023003113 is 31130032023031.
13032023003113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7413928459609 + 5618094543504 = 2722853^2 + 2370252^2 .
It is a cyclic number.
It is not a de Polignac number, because 13032023003113 - 25 = 13032023003081 is a prime.
It is not a weakly prime, because it can be changed into another prime (13032023003183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516011501556 + 6516011501557.
It is an arithmetic number, because the mean of its divisors is an integer number (6516011501557).
Almost surely, 213032023003113 is an apocalyptic number.
It is an amenable number.
13032023003113 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032023003113 is an equidigital number, since it uses as much as digits as its factorization.
13032023003113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13032023003113 its reverse (31130032023031), we get a palindrome (44162055026144).
The spelling of 13032023003113 in words is "thirteen trillion, thirty-two billion, twenty-three million, three thousand, one hundred thirteen".
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