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13032023003113 is a prime number
BaseRepresentation
bin1011110110100100000100…
…0110100000111111101001
31201010211221002102122012211
42331221001012200333221
53202004040342044423
643414455000405121
72513350451546452
oct275510106407751
951124832378184
1013032023003113
114174939271a24
12156583a1767a1
13736bb71bcb7a
14330a78dd6129
15178ed5bb910d
hexbda411a0fe9

13032023003113 has 2 divisors, whose sum is σ = 13032023003114. Its totient is φ = 13032023003112.

The previous prime is 13032023003081. The next prime is 13032023003183. The reversal of 13032023003113 is 31130032023031.

13032023003113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7413928459609 + 5618094543504 = 2722853^2 + 2370252^2 .

It is a cyclic number.

It is not a de Polignac number, because 13032023003113 - 25 = 13032023003081 is a prime.

It is not a weakly prime, because it can be changed into another prime (13032023003183) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516011501556 + 6516011501557.

It is an arithmetic number, because the mean of its divisors is an integer number (6516011501557).

Almost surely, 213032023003113 is an apocalyptic number.

It is an amenable number.

13032023003113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13032023003113 is an equidigital number, since it uses as much as digits as its factorization.

13032023003113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 22.

Adding to 13032023003113 its reverse (31130032023031), we get a palindrome (44162055026144).

The spelling of 13032023003113 in words is "thirteen trillion, thirty-two billion, twenty-three million, three thousand, one hundred thirteen".