Base | Representation |
---|---|
bin | 1011110110100100000110… |
… | …0101000100010010000011 |
3 | 1201010211221122111112022012 |
4 | 2331221001211010102003 |
5 | 3202004044414340341 |
6 | 43414455444203135 |
7 | 2513350606614056 |
oct | 275510145042203 |
9 | 51124848445265 |
10 | 13032031011971 |
11 | 4174942842114 |
12 | 15658409994ab |
13 | 736bb8a6533a |
14 | 330a7a0bca9d |
15 | 178ed674c0eb |
hex | bda41944483 |
13032031011971 has 2 divisors, whose sum is σ = 13032031011972. Its totient is φ = 13032031011970.
The previous prime is 13032031011911. The next prime is 13032031012009. The reversal of 13032031011971 is 17911013023031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13032031011971 is a prime.
It is not a weakly prime, because it can be changed into another prime (13032031011911) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516015505985 + 6516015505986.
It is an arithmetic number, because the mean of its divisors is an integer number (6516015505986).
Almost surely, 213032031011971 is an apocalyptic number.
13032031011971 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032031011971 is an equidigital number, since it uses as much as digits as its factorization.
13032031011971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3402, while the sum is 32.
The spelling of 13032031011971 in words is "thirteen trillion, thirty-two billion, thirty-one million, eleven thousand, nine hundred seventy-one".
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