Base | Representation |
---|---|
bin | 10010111101101101100… |
… | …111011011011110111001 |
3 | 11121120211020022212002221 |
4 | 102331231213123132321 |
5 | 132322440310042132 |
6 | 2434404401524041 |
7 | 163103601306034 |
oct | 22755547333671 |
9 | 4546736285087 |
10 | 1303214143417 |
11 | 46276545576a |
12 | 1906a3943621 |
13 | 95b7ac78754 |
14 | 4710c3b601b |
15 | 23d761b8e97 |
hex | 12f6d9db7b9 |
1303214143417 has 2 divisors, whose sum is σ = 1303214143418. Its totient is φ = 1303214143416.
The previous prime is 1303214143379. The next prime is 1303214143481. The reversal of 1303214143417 is 7143414123031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1258803217296 + 44410926121 = 1121964^2 + 210739^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303214143417 - 27 = 1303214143289 is a prime.
It is not a weakly prime, because it can be changed into another prime (1303214543417) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651607071708 + 651607071709.
It is an arithmetic number, because the mean of its divisors is an integer number (651607071709).
Almost surely, 21303214143417 is an apocalyptic number.
It is an amenable number.
1303214143417 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303214143417 is an equidigital number, since it uses as much as digits as its factorization.
1303214143417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 34.
Adding to 1303214143417 its reverse (7143414123031), we get a palindrome (8446628266448).
The spelling of 1303214143417 in words is "one trillion, three hundred three billion, two hundred fourteen million, one hundred forty-three thousand, four hundred seventeen".
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