Base | Representation |
---|---|
bin | 11101101000011011110101… |
… | …110001111011110101101011 |
3 | 122002102122220201201100110102 |
4 | 131220123311301323311223 |
5 | 114040143444412001212 |
6 | 1141101035433540015 |
7 | 36310312113603053 |
oct | 3550336561736553 |
9 | 562378821640412 |
10 | 130322021203307 |
11 | 385852935324aa |
12 | 1274934527460b |
13 | 579441074aabb |
14 | 2427895c00563 |
15 | 100ee951735c2 |
hex | 7686f5c7bd6b |
130322021203307 has 2 divisors, whose sum is σ = 130322021203308. Its totient is φ = 130322021203306.
The previous prime is 130322021203291. The next prime is 130322021203349. The reversal of 130322021203307 is 703302120223031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130322021203307 - 24 = 130322021203291 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 130322021203307.
It is not a weakly prime, because it can be changed into another prime (130322021203357) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161010601653 + 65161010601654.
It is an arithmetic number, because the mean of its divisors is an integer number (65161010601654).
Almost surely, 2130322021203307 is an apocalyptic number.
130322021203307 is a deficient number, since it is larger than the sum of its proper divisors (1).
130322021203307 is an equidigital number, since it uses as much as digits as its factorization.
130322021203307 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9072, while the sum is 29.
Adding to 130322021203307 its reverse (703302120223031), we get a palindrome (833624141426338).
The spelling of 130322021203307 in words is "one hundred thirty trillion, three hundred twenty-two billion, twenty-one million, two hundred three thousand, three hundred seven".
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