Base | Representation |
---|---|
bin | 1011110110100100110110… |
… | …0100100011011001000111 |
3 | 1201010212110200002010200011 |
4 | 2331221031210203121013 |
5 | 3202010002421010342 |
6 | 43414531432331051 |
7 | 2513355601664233 |
oct | 275511544433107 |
9 | 51125420063604 |
10 | 13032232203847 |
11 | 4174a3636959a |
12 | 1565898243a87 |
13 | 736c1b648c9c |
14 | 330a98ad15c3 |
15 | 178ee923e717 |
hex | bda4d923647 |
13032232203847 has 2 divisors, whose sum is σ = 13032232203848. Its totient is φ = 13032232203846.
The previous prime is 13032232203791. The next prime is 13032232203901. The reversal of 13032232203847 is 74830223223031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13032232203847 - 239 = 12482476389959 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13032232203247) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516116101923 + 6516116101924.
It is an arithmetic number, because the mean of its divisors is an integer number (6516116101924).
Almost surely, 213032232203847 is an apocalyptic number.
13032232203847 is a deficient number, since it is larger than the sum of its proper divisors (1).
13032232203847 is an equidigital number, since it uses as much as digits as its factorization.
13032232203847 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 290304, while the sum is 40.
Adding to 13032232203847 its reverse (74830223223031), we get a palindrome (87862455426878).
The spelling of 13032232203847 in words is "thirteen trillion, thirty-two billion, two hundred thirty-two million, two hundred three thousand, eight hundred forty-seven".
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