Base | Representation |
---|---|
bin | 11101101000011100110000… |
… | …001100110101000111110011 |
3 | 122002102202110001000001112221 |
4 | 131220130300030311013303 |
5 | 114040203001320112321 |
6 | 1141101321005301511 |
7 | 36310345314552532 |
oct | 3550346014650763 |
9 | 562382401001487 |
10 | 130323001332211 |
11 | 38585746813896 |
12 | 12749579564897 |
13 | 579453881b42c |
14 | 242794a058319 |
15 | 101000122be41 |
hex | 7687303351f3 |
130323001332211 has 2 divisors, whose sum is σ = 130323001332212. Its totient is φ = 130323001332210.
The previous prime is 130323001332137. The next prime is 130323001332281. The reversal of 130323001332211 is 112233100323031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130323001332211 - 211 = 130323001330163 is a prime.
It is a super-2 number, since 2×1303230013322112 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (130323001332281) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161500666105 + 65161500666106.
It is an arithmetic number, because the mean of its divisors is an integer number (65161500666106).
Almost surely, 2130323001332211 is an apocalyptic number.
130323001332211 is a deficient number, since it is larger than the sum of its proper divisors (1).
130323001332211 is an equidigital number, since it uses as much as digits as its factorization.
130323001332211 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1944, while the sum is 25.
Adding to 130323001332211 its reverse (112233100323031), we get a palindrome (242556101655242).
The spelling of 130323001332211 in words is "one hundred thirty trillion, three hundred twenty-three billion, one million, three hundred thirty-two thousand, two hundred eleven".
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