Base | Representation |
---|---|
bin | 10010111101101110100… |
… | …111110001100011000011 |
3 | 11121120212102001211002122 |
4 | 102331232213301203003 |
5 | 132323004114323021 |
6 | 2434410203234455 |
7 | 163104164550506 |
oct | 22755647614303 |
9 | 4546772054078 |
10 | 1303231011011 |
11 | 462773a26626 |
12 | 1906a9518a2b |
13 | 95b81603187 |
14 | 4711072713d |
15 | 23d778ebbab |
hex | 12f6e9f18c3 |
1303231011011 has 2 divisors, whose sum is σ = 1303231011012. Its totient is φ = 1303231011010.
The previous prime is 1303231010993. The next prime is 1303231011013. The reversal of 1303231011011 is 1101101323031.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1303231011011 is a prime.
It is a super-2 number, since 2×13032310110112 (a number of 25 digits) contains 22 as substring.
Together with 1303231011013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1303231011013) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651615505505 + 651615505506.
It is an arithmetic number, because the mean of its divisors is an integer number (651615505506).
Almost surely, 21303231011011 is an apocalyptic number.
1303231011011 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303231011011 is an equidigital number, since it uses as much as digits as its factorization.
1303231011011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1303231011011 its reverse (1101101323031), we get a palindrome (2404332334042).
The spelling of 1303231011011 in words is "one trillion, three hundred three billion, two hundred thirty-one million, eleven thousand, eleven".
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