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130323131221 is a prime number
BaseRepresentation
bin111100101011111011…
…1010010101101010101
3110110101102222000022211
41321113313102231111
54113400210144341
6135511500553421
712262346223613
oct1712767225525
9413342860284
10130323131221
11502a7012428
1221310b52871
13c39bb1103a
1464443806b3
1535cb3e1181
hex1e57dd2b55

130323131221 has 2 divisors, whose sum is σ = 130323131222. Its totient is φ = 130323131220.

The previous prime is 130323131209. The next prime is 130323131227. The reversal of 130323131221 is 122131323031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 104319956196 + 26003175025 = 322986^2 + 161255^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-130323131221 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130323131192 and 130323131201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130323131227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65161565610 + 65161565611.

It is an arithmetic number, because the mean of its divisors is an integer number (65161565611).

Almost surely, 2130323131221 is an apocalyptic number.

It is an amenable number.

130323131221 is a deficient number, since it is larger than the sum of its proper divisors (1).

130323131221 is an equidigital number, since it uses as much as digits as its factorization.

130323131221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 130323131221 its reverse (122131323031), we get a palindrome (252454454252).

The spelling of 130323131221 in words is "one hundred thirty billion, three hundred twenty-three million, one hundred thirty-one thousand, two hundred twenty-one".