Base | Representation |
---|---|
bin | 111100101011111101… |
… | …1110111011110111001 |
3 | 110110101112012221022210 |
4 | 1321113323313132321 |
5 | 4113401012033200 |
6 | 135511542405333 |
7 | 12262362350052 |
oct | 1712773673671 |
9 | 413345187283 |
10 | 130324330425 |
11 | 502a7761403 |
12 | 21311430849 |
13 | c39c140b23 |
14 | 64445b3729 |
15 | 35cb57b650 |
hex | 1e57ef77b9 |
130324330425 has 24 divisors (see below), whose sum is σ = 216660021760. Its totient is φ = 69122289600.
The previous prime is 130324330403. The next prime is 130324330439. The reversal of 130324330425 is 524033423031.
It is not a de Polignac number, because 130324330425 - 211 = 130324328377 is a prime.
It is a super-2 number, since 2×1303243304252 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130324330392 and 130324330401.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 4786585 + ... + 4813734.
Almost surely, 2130324330425 is an apocalyptic number.
130324330425 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
130324330425 is a deficient number, since it is larger than the sum of its proper divisors (86335691335).
130324330425 is a wasteful number, since it uses less digits than its factorization.
130324330425 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9600513 (or 9600508 counting only the distinct ones).
The product of its (nonzero) digits is 25920, while the sum is 30.
Adding to 130324330425 its reverse (524033423031), we get a palindrome (654357753456).
The spelling of 130324330425 in words is "one hundred thirty billion, three hundred twenty-four million, three hundred thirty thousand, four hundred twenty-five".
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