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1303244451101 is a prime number
BaseRepresentation
bin10010111101101111011…
…011000010110100011101
311121120220100100122102202
4102331233123002310131
5132323021034413401
62434411403301245
7163104420025445
oct22755733026435
94546810318382
101303244451101
1146278057633a
121906b1b1a825
1395b8432a7a8
1447112425125
1523d78ba406b
hex12f6f6c2d1d

1303244451101 has 2 divisors, whose sum is σ = 1303244451102. Its totient is φ = 1303244451100.

The previous prime is 1303244451097. The next prime is 1303244451127. The reversal of 1303244451101 is 1011544423031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 855985788025 + 447258663076 = 925195^2 + 668774^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303244451101 - 22 = 1303244451097 is a prime.

It is a super-2 number, since 2×13032444511012 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303244451401) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651622225550 + 651622225551.

It is an arithmetic number, because the mean of its divisors is an integer number (651622225551).

Almost surely, 21303244451101 is an apocalyptic number.

It is an amenable number.

1303244451101 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303244451101 is an equidigital number, since it uses as much as digits as its factorization.

1303244451101 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 29.

Adding to 1303244451101 its reverse (1011544423031), we get a palindrome (2314788874132).

The spelling of 1303244451101 in words is "one trillion, three hundred three billion, two hundred forty-four million, four hundred fifty-one thousand, one hundred one".