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1303253332481 is a prime number
BaseRepresentation
bin10010111101101111111…
…100111011001000000001
311121120220222001212101202
4102331233330323020001
5132323030323114411
62434412321510545
7163104555355622
oct22755774731001
94546828055352
101303253332481
11462785592021
121906b4aa2455
1395b8611a149
1447113697a49
1523d7985a83b
hex12f6ff3b201

1303253332481 has 2 divisors, whose sum is σ = 1303253332482. Its totient is φ = 1303253332480.

The previous prime is 1303253332477. The next prime is 1303253332553. The reversal of 1303253332481 is 1842333523031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 736069623025 + 567183709456 = 857945^2 + 753116^2 .

It is a cyclic number.

It is not a de Polignac number, because 1303253332481 - 22 = 1303253332477 is a prime.

It is a super-3 number, since 3×13032533324813 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1303253332411) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651626666240 + 651626666241.

It is an arithmetic number, because the mean of its divisors is an integer number (651626666241).

Almost surely, 21303253332481 is an apocalyptic number.

It is an amenable number.

1303253332481 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303253332481 is an equidigital number, since it uses as much as digits as its factorization.

1303253332481 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 155520, while the sum is 38.

The spelling of 1303253332481 in words is "one trillion, three hundred three billion, two hundred fifty-three million, three hundred thirty-two thousand, four hundred eighty-one".