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130327260483221 is a prime number
BaseRepresentation
bin11101101000100000101110…
…000100001100111010010101
3122002110011102212100100100122
4131220200232010030322111
5114040240212140430341
61141103303353521325
736310556003003444
oct3550405604147225
9562404385310318
10130327260483221
1138587531a10aaa
121274a367a13245
135794a67037829
142427c3198ad5b
1510101a00e294b
hex76882e10ce95

130327260483221 has 2 divisors, whose sum is σ = 130327260483222. Its totient is φ = 130327260483220.

The previous prime is 130327260483191. The next prime is 130327260483263. The reversal of 130327260483221 is 122384062723031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 90112511403121 + 40214749080100 = 9492761^2 + 6341510^2 .

It is a cyclic number.

It is not a de Polignac number, because 130327260483221 - 230 = 130326186741397 is a prime.

It is a super-2 number, since 2×1303272604832212 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130327220483221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65163630241610 + 65163630241611.

It is an arithmetic number, because the mean of its divisors is an integer number (65163630241611).

Almost surely, 2130327260483221 is an apocalyptic number.

It is an amenable number.

130327260483221 is a deficient number, since it is larger than the sum of its proper divisors (1).

130327260483221 is an equidigital number, since it uses as much as digits as its factorization.

130327260483221 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 580608, while the sum is 44.

The spelling of 130327260483221 in words is "one hundred thirty trillion, three hundred twenty-seven billion, two hundred sixty million, four hundred eighty-three thousand, two hundred twenty-one".