Base | Representation |
---|---|
bin | 10010111101110010110… |
… | …111010110001010001101 |
3 | 11121121001101000200202211 |
4 | 102331302313112022031 |
5 | 132323130330430442 |
6 | 2434421225150421 |
7 | 163106020634425 |
oct | 22756267261215 |
9 | 4547041020684 |
10 | 1303302201997 |
11 | 462800130454 |
12 | 19070932b411 |
13 | 95b9329ab13 |
14 | 47119d79485 |
15 | 23d7dcb0617 |
hex | 12f72dd628d |
1303302201997 has 2 divisors, whose sum is σ = 1303302201998. Its totient is φ = 1303302201996.
The previous prime is 1303302201991. The next prime is 1303302202039. The reversal of 1303302201997 is 7991022033031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 855391915876 + 447910286121 = 924874^2 + 669261^2 .
It is a cyclic number.
It is not a de Polignac number, because 1303302201997 - 211 = 1303302199949 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303302201991) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651651100998 + 651651100999.
It is an arithmetic number, because the mean of its divisors is an integer number (651651100999).
Almost surely, 21303302201997 is an apocalyptic number.
It is an amenable number.
1303302201997 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303302201997 is an equidigital number, since it uses as much as digits as its factorization.
1303302201997 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 61236, while the sum is 40.
The spelling of 1303302201997 in words is "one trillion, three hundred three billion, three hundred two million, two hundred one thousand, nine hundred ninety-seven".
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