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13033099139 is a prime number
BaseRepresentation
bin11000010001101010…
…10100111110000011
31020122022002000221112
430020311110332003
5203142433133024
65553132313535
7640654341404
oct141065247603
936568060845
1013033099139
115588932315
1226389128ab
1312c91c04a8
148b8d039ab
155142de00e
hex308d54f83

13033099139 has 2 divisors, whose sum is σ = 13033099140. Its totient is φ = 13033099138.

The previous prime is 13033099127. The next prime is 13033099141. The reversal of 13033099139 is 93199033031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13033099139 - 212 = 13033095043 is a prime.

Together with 13033099141, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13033099096 and 13033099105.

It is not a weakly prime, because it can be changed into another prime (13033099439) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516549569 + 6516549570.

It is an arithmetic number, because the mean of its divisors is an integer number (6516549570).

Almost surely, 213033099139 is an apocalyptic number.

13033099139 is a deficient number, since it is larger than the sum of its proper divisors (1).

13033099139 is an equidigital number, since it uses as much as digits as its factorization.

13033099139 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 59049, while the sum is 41.

The spelling of 13033099139 in words is "thirteen billion, thirty-three million, ninety-nine thousand, one hundred thirty-nine".