Base | Representation |
---|---|
bin | 1011110110101000000111… |
… | …1101010001111100101111 |
3 | 1201010221201220212202020010 |
4 | 2331222001331101330233 |
5 | 3202013302420214411 |
6 | 43415154550224303 |
7 | 2513416433332254 |
oct | 275520175217457 |
9 | 51127656782203 |
10 | 13033111101231 |
11 | 4175347498171 |
12 | 1565aa2655093 |
13 | 73702b764400 |
14 | 330b3d71742b |
15 | 17904b49d7a6 |
hex | bda81f51f2f |
13033111101231 has 48 divisors (see below), whose sum is σ = 19414762214400. Its totient is φ = 7769438741376.
The previous prime is 13033111101217. The next prime is 13033111101271. The reversal of 13033111101231 is 13210111133031.
It is not a de Polignac number, because 13033111101231 - 233 = 13024521166639 is a prime.
It is a super-2 number, since 2×130331111012312 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13033111101198 and 13033111101207.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13033111101271) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 946971 + ... + 5192588.
It is an arithmetic number, because the mean of its divisors is an integer number (404474212800).
Almost surely, 213033111101231 is an apocalyptic number.
13033111101231 is a deficient number, since it is larger than the sum of its proper divisors (6381651113169).
13033111101231 is a wasteful number, since it uses less digits than its factorization.
13033111101231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6139720 (or 6139707 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 13033111101231 its reverse (13210111133031), we get a palindrome (26243222234262).
The spelling of 13033111101231 in words is "thirteen trillion, thirty-three billion, one hundred eleven million, one hundred one thousand, two hundred thirty-one".
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