Base | Representation |
---|---|
bin | 111100101100001010… |
… | …1110011110010010011 |
3 | 110110102000000102222221 |
4 | 1321120111303302103 |
5 | 4113404232143102 |
6 | 135512344241511 |
7 | 12262504222636 |
oct | 1713025636223 |
9 | 413360012887 |
10 | 130331131027 |
11 | 50300586839 |
12 | 21313770297 |
13 | c3a0682356 |
14 | 6445463c1d |
15 | 35cbe71637 |
hex | 1e58573c93 |
130331131027 has 2 divisors, whose sum is σ = 130331131028. Its totient is φ = 130331131026.
The previous prime is 130331131003. The next prime is 130331131067. The reversal of 130331131027 is 720131133031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130331131027 - 215 = 130331098259 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130331130992 and 130331131010.
It is not a weakly prime, because it can be changed into another prime (130331131067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65165565513 + 65165565514.
It is an arithmetic number, because the mean of its divisors is an integer number (65165565514).
Almost surely, 2130331131027 is an apocalyptic number.
130331131027 is a deficient number, since it is larger than the sum of its proper divisors (1).
130331131027 is an equidigital number, since it uses as much as digits as its factorization.
130331131027 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1134, while the sum is 25.
Adding to 130331131027 its reverse (720131133031), we get a palindrome (850462264058).
The spelling of 130331131027 in words is "one hundred thirty billion, three hundred thirty-one million, one hundred thirty-one thousand, twenty-seven".
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