Base | Representation |
---|---|
bin | 1011110110101000001010… |
… | …0011110011111101001001 |
3 | 1201010221202121212220212102 |
4 | 2331222002203303331021 |
5 | 3202013313011430433 |
6 | 43415155550523145 |
7 | 2513416615231454 |
oct | 275520243637511 |
9 | 51127677786772 |
10 | 13033121201993 |
11 | 4175352167002 |
12 | 1565aa5b064b5 |
13 | 73703088caa9 |
14 | 330b40bc649b |
15 | 17904c2e64e8 |
hex | bda828f3f49 |
13033121201993 has 2 divisors, whose sum is σ = 13033121201994. Its totient is φ = 13033121201992.
The previous prime is 13033121201981. The next prime is 13033121202043. The reversal of 13033121201993 is 39910212133031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10116038247184 + 2917082954809 = 3180572^2 + 1707947^2 .
It is an emirp because it is prime and its reverse (39910212133031) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13033121201993 - 26 = 13033121201929 is a prime.
It is a super-2 number, since 2×130331212019932 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13033121201923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516560600996 + 6516560600997.
It is an arithmetic number, because the mean of its divisors is an integer number (6516560600997).
Almost surely, 213033121201993 is an apocalyptic number.
It is an amenable number.
13033121201993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033121201993 is an equidigital number, since it uses as much as digits as its factorization.
13033121201993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 26244, while the sum is 38.
The spelling of 13033121201993 in words is "thirteen trillion, thirty-three billion, one hundred twenty-one million, two hundred one thousand, nine hundred ninety-three".
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