Base | Representation |
---|---|
bin | 11101101000100101001001… |
… | …010011011111011010100100 |
3 | 122002110121201000222221010002 |
4 | 131220211021103133122210 |
5 | 114040324430141141200 |
6 | 1141105411104520432 |
7 | 36311114524001453 |
oct | 3550451123373244 |
9 | 562417630887102 |
10 | 130332012443300 |
11 | 38589550303a38 |
12 | 1274b273320118 |
13 | 579534368bc25 |
14 | 2428162b22b9a |
15 | 101037c3a0bd5 |
hex | 7689494df6a4 |
130332012443300 has 18 divisors (see below), whose sum is σ = 282820467002178. Its totient is φ = 52132804977280.
The previous prime is 130332012443287. The next prime is 130332012443323. The reversal of 130332012443300 is 3344210233031.
It can be written as a sum of positive squares in 3 ways, for example, as 1622805923236 + 128709206520064 = 1273894^2 + 11345008^2 .
It is an unprimeable number.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 651660062117 + ... + 651660062316.
Almost surely, 2130332012443300 is an apocalyptic number.
130332012443300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130332012443300 is an abundant number, since it is smaller than the sum of its proper divisors (152488454558878).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130332012443300 is a wasteful number, since it uses less digits than its factorization.
130332012443300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1303320124447 (or 1303320124440 counting only the distinct ones).
The product of its (nonzero) digits is 15552, while the sum is 29.
Adding to 130332012443300 its reverse (3344210233031), we get a palindrome (133676222676331).
The spelling of 130332012443300 in words is "one hundred thirty trillion, three hundred thirty-two billion, twelve million, four hundred forty-three thousand, three hundred".
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