Base | Representation |
---|---|
bin | 111100101100001100… |
… | …1100110000011000011 |
3 | 110110102001212212011221 |
4 | 1321120121212003003 |
5 | 4113410010421311 |
6 | 135512421415511 |
7 | 12262515524644 |
oct | 1713031460303 |
9 | 413361785157 |
10 | 130332123331 |
11 | 503010a4323 |
12 | 21313b6a597 |
13 | c3a093bc07 |
14 | 64456416cb |
15 | 35cc0ba671 |
hex | 1e586660c3 |
130332123331 has 2 divisors, whose sum is σ = 130332123332. Its totient is φ = 130332123330.
The previous prime is 130332123293. The next prime is 130332123349. The reversal of 130332123331 is 133321233031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130332123331 - 219 = 130331599043 is a prime.
It is a super-2 number, since 2×1303321233312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130332123296 and 130332123305.
It is not a weakly prime, because it can be changed into another prime (130332123371) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65166061665 + 65166061666.
It is an arithmetic number, because the mean of its divisors is an integer number (65166061666).
Almost surely, 2130332123331 is an apocalyptic number.
130332123331 is a deficient number, since it is larger than the sum of its proper divisors (1).
130332123331 is an equidigital number, since it uses as much as digits as its factorization.
130332123331 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2916, while the sum is 25.
Adding to 130332123331 its reverse (133321233031), we get a palindrome (263653356362).
The spelling of 130332123331 in words is "one hundred thirty billion, three hundred thirty-two million, one hundred twenty-three thousand, three hundred thirty-one".
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