Base | Representation |
---|---|
bin | 1011110110101000100010… |
… | …0001011000111000011111 |
3 | 1201010222000121002212122112 |
4 | 2331222020201120320133 |
5 | 3202014014113330421 |
6 | 43415213522504235 |
7 | 2513422241401565 |
oct | 275521041307037 |
9 | 51128017085575 |
10 | 13033221230111 |
11 | 41753a3677675 |
12 | 1565b1350507b |
13 | 737048513324 |
14 | 330b501c3a35 |
15 | 179055ea445b |
hex | bda88858e1f |
13033221230111 has 2 divisors, whose sum is σ = 13033221230112. Its totient is φ = 13033221230110.
The previous prime is 13033221230093. The next prime is 13033221230119. The reversal of 13033221230111 is 11103212233031.
13033221230111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13033221230111 - 230 = 13032147488287 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13033221230119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6516610615055 + 6516610615056.
It is an arithmetic number, because the mean of its divisors is an integer number (6516610615056).
Almost surely, 213033221230111 is an apocalyptic number.
13033221230111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13033221230111 is an equidigital number, since it uses as much as digits as its factorization.
13033221230111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13033221230111 its reverse (11103212233031), we get a palindrome (24136433463142).
The spelling of 13033221230111 in words is "thirteen trillion, thirty-three billion, two hundred twenty-one million, two hundred thirty thousand, one hundred eleven".
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