Base | Representation |
---|---|
bin | 10010111101110100001… |
… | …011011001000110001101 |
3 | 11121121002220111001011120 |
4 | 102331310023121012031 |
5 | 132323202000443000 |
6 | 2434423333311153 |
7 | 163106406126144 |
oct | 22756413310615 |
9 | 4547086431146 |
10 | 1303324234125 |
11 | 462811609521 |
12 | 1907147954b9 |
13 | 95b97a13194 |
14 | 4711cc7275b |
15 | 23d80bb36a0 |
hex | 12f742d918d |
1303324234125 has 32 divisors (see below), whose sum is σ = 2168821968768. Its totient is φ = 695077270400.
The previous prime is 1303324234109. The next prime is 1303324234129. The reversal of 1303324234125 is 5214324233031.
It is not a de Polignac number, because 1303324234125 - 24 = 1303324234109 is a prime.
It is a Curzon number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1303324234129) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 11313817 + ... + 11428433.
It is an arithmetic number, because the mean of its divisors is an integer number (67775686524).
Almost surely, 21303324234125 is an apocalyptic number.
1303324234125 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1303324234125 is a deficient number, since it is larger than the sum of its proper divisors (865497734643).
1303324234125 is a wasteful number, since it uses less digits than its factorization.
1303324234125 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 144958 (or 144948 counting only the distinct ones).
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 1303324234125 its reverse (5214324233031), we get a palindrome (6517648467156).
The spelling of 1303324234125 in words is "one trillion, three hundred three billion, three hundred twenty-four million, two hundred thirty-four thousand, one hundred twenty-five".
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