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1303331021221 is a prime number
BaseRepresentation
bin10010111101110100100…
…101010010000110100101
311121121010101020212022111
4102331310211102012211
5132323210220134341
62434424135001021
7163106520614455
oct22756445220645
94547111225274
101303331021221
11462815424799
12190716b09171
1395b9924b508
144711db1bd65
1523d815a4681
hex12f749521a5

1303331021221 has 2 divisors, whose sum is σ = 1303331021222. Its totient is φ = 1303331021220.

The previous prime is 1303331021183. The next prime is 1303331021233. The reversal of 1303331021221 is 1221201333031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1038738064225 + 264592956996 = 1019185^2 + 514386^2 .

It is an emirp because it is prime and its reverse (1221201333031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1303331021221 - 217 = 1303330890149 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1303331021192 and 1303331021201.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303331021021) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651665510610 + 651665510611.

It is an arithmetic number, because the mean of its divisors is an integer number (651665510611).

Almost surely, 21303331021221 is an apocalyptic number.

It is an amenable number.

1303331021221 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303331021221 is an equidigital number, since it uses as much as digits as its factorization.

1303331021221 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1303331021221 its reverse (1221201333031), we get a palindrome (2524532354252).

The spelling of 1303331021221 in words is "one trillion, three hundred three billion, three hundred thirty-one million, twenty-one thousand, two hundred twenty-one".