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130333133131 is a prime number
BaseRepresentation
bin111100101100001110…
…1011100100101001011
3110110102010210011100221
41321120131130211023
54113410240230011
6135512455210511
712262530231655
oct1713035344513
9413363704327
10130333133131
1150301723a73
1221314376a37
13c3a0c03726
1464458256d5
1535cc219971
hex1e5875c94b

130333133131 has 2 divisors, whose sum is σ = 130333133132. Its totient is φ = 130333133130.

The previous prime is 130333133111. The next prime is 130333133197. The reversal of 130333133131 is 131331333031.

It is a weak prime.

It is an emirp because it is prime and its reverse (131331333031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 130333133131 - 233 = 121743198539 is a prime.

It is a super-2 number, since 2×1303331331312 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130333133096 and 130333133105.

It is not a weakly prime, because it can be changed into another prime (130333133111) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65166566565 + 65166566566.

It is an arithmetic number, because the mean of its divisors is an integer number (65166566566).

Almost surely, 2130333133131 is an apocalyptic number.

130333133131 is a deficient number, since it is larger than the sum of its proper divisors (1).

130333133131 is an equidigital number, since it uses as much as digits as its factorization.

130333133131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187, while the sum is 25.

Adding to 130333133131 its reverse (131331333031), we get a palindrome (261664466162).

The spelling of 130333133131 in words is "one hundred thirty billion, three hundred thirty-three million, one hundred thirty-three thousand, one hundred thirty-one".