Base | Representation |
---|---|
bin | 10010111101110101001… |
… | …000000100101000011111 |
3 | 11121121011000102012102022 |
4 | 102331311020010220133 |
5 | 132323220034003322 |
6 | 2434425102250355 |
7 | 163106661260135 |
oct | 22756510045037 |
9 | 4547130365368 |
10 | 1303340141087 |
11 | 46281a593676 |
12 | 190719b869bb |
13 | 95b9b0c259a |
14 | 47121013755 |
15 | 23d822a6942 |
hex | 12f75204a1f |
1303340141087 has 2 divisors, whose sum is σ = 1303340141088. Its totient is φ = 1303340141086.
The previous prime is 1303340141069. The next prime is 1303340141167. The reversal of 1303340141087 is 7801410433031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1303340141087 - 216 = 1303340075551 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1303340141287) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651670070543 + 651670070544.
It is an arithmetic number, because the mean of its divisors is an integer number (651670070544).
Almost surely, 21303340141087 is an apocalyptic number.
1303340141087 is a deficient number, since it is larger than the sum of its proper divisors (1).
1303340141087 is an equidigital number, since it uses as much as digits as its factorization.
1303340141087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 1303340141087 in words is "one trillion, three hundred three billion, three hundred forty million, one hundred forty-one thousand, eighty-seven".
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