Base | Representation |
---|---|
bin | 1011110110101011011100… |
… | …0101011100010101011011 |
3 | 1201011001001001002010001121 |
4 | 2331222313011130111123 |
5 | 3202022114110331441 |
6 | 43415423230430111 |
7 | 2513450505460243 |
oct | 275526705342533 |
9 | 51131031063047 |
10 | 13034002433371 |
11 | 417576463a1a7 |
12 | 15660b1062337 |
13 | 73714131468a |
14 | 330bc5c58b23 |
15 | 17909e866dd1 |
hex | bdab715c55b |
13034002433371 has 2 divisors, whose sum is σ = 13034002433372. Its totient is φ = 13034002433370.
The previous prime is 13034002433339. The next prime is 13034002433399. The reversal of 13034002433371 is 17333420043031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13034002433371 - 25 = 13034002433339 is a prime.
It is a super-2 number, since 2×130340024333712 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13034002433671) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517001216685 + 6517001216686.
It is an arithmetic number, because the mean of its divisors is an integer number (6517001216686).
Almost surely, 213034002433371 is an apocalyptic number.
13034002433371 is a deficient number, since it is larger than the sum of its proper divisors (1).
13034002433371 is an equidigital number, since it uses as much as digits as its factorization.
13034002433371 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54432, while the sum is 34.
The spelling of 13034002433371 in words is "thirteen trillion, thirty-four billion, two million, four hundred thirty-three thousand, three hundred seventy-one".
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