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130340122120051 is a prime number
BaseRepresentation
bin11101101000101100101100…
…101011011100111101110011
3122002111101122012210012020021
4131220230230223130331303
5114040443032230320201
61141113231523224311
736311522506056064
oct3550545453347563
9562441565705207
10130340122120051
1138591a31a82128
1212750957218097
13579603685321c
1424286d1bba56b
1510106a4312ea1
hex768b2cadcf73

130340122120051 has 2 divisors, whose sum is σ = 130340122120052. Its totient is φ = 130340122120050.

The previous prime is 130340122120001. The next prime is 130340122120069. The reversal of 130340122120051 is 150021221043031.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 130340122120051 - 231 = 130337974636403 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130340122119998 and 130340122120025.

It is not a weakly prime, because it can be changed into another prime (130340122120001) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65170061060025 + 65170061060026.

It is an arithmetic number, because the mean of its divisors is an integer number (65170061060026).

Almost surely, 2130340122120051 is an apocalyptic number.

130340122120051 is a deficient number, since it is larger than the sum of its proper divisors (1).

130340122120051 is an equidigital number, since it uses as much as digits as its factorization.

130340122120051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 130340122120051 its reverse (150021221043031), we get a palindrome (280361343163082).

The spelling of 130340122120051 in words is "one hundred thirty trillion, three hundred forty billion, one hundred twenty-two million, one hundred twenty thousand, fifty-one".