Base | Representation |
---|---|
bin | 1011110110101011111000… |
… | …0111000100111000011111 |
3 | 1201011001100020212110120111 |
4 | 2331222332013010320133 |
5 | 3202022334244131421 |
6 | 43415443041030451 |
7 | 2513453436364006 |
oct | 275527607047037 |
9 | 51131306773514 |
10 | 13034120302111 |
11 | 4175815125787 |
12 | 1566124625427 |
13 | 73715c8734ac |
14 | 330bd777bc3d |
15 | 1790a9d9aee1 |
hex | bdabe1c4e1f |
13034120302111 has 2 divisors, whose sum is σ = 13034120302112. Its totient is φ = 13034120302110.
The previous prime is 13034120302087. The next prime is 13034120302139. The reversal of 13034120302111 is 11120302143031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13034120302111 - 223 = 13034111913503 is a prime.
It is a super-3 number, since 3×130341203021113 (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13034120302141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517060151055 + 6517060151056.
It is an arithmetic number, because the mean of its divisors is an integer number (6517060151056).
Almost surely, 213034120302111 is an apocalyptic number.
13034120302111 is a deficient number, since it is larger than the sum of its proper divisors (1).
13034120302111 is an equidigital number, since it uses as much as digits as its factorization.
13034120302111 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 13034120302111 its reverse (11120302143031), we get a palindrome (24154422445142).
The spelling of 13034120302111 in words is "thirteen trillion, thirty-four billion, one hundred twenty million, three hundred two thousand, one hundred eleven".
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