Base | Representation |
---|---|
bin | 111100101100100011… |
… | …0111111000000010001 |
3 | 110110102220021101010121 |
4 | 1321121012333000101 |
5 | 4113421032201113 |
6 | 135513524430241 |
7 | 12263021623021 |
oct | 1713106770021 |
9 | 413386241117 |
10 | 130344022033 |
11 | 50307890a65 |
12 | 21317b48381 |
13 | c3a3246a74 |
14 | 644705ba81 |
15 | 35cd16ae8d |
hex | 1e591bf011 |
130344022033 has 2 divisors, whose sum is σ = 130344022034. Its totient is φ = 130344022032.
The previous prime is 130344022027. The next prime is 130344022093. The reversal of 130344022033 is 330220443031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 130246644609 + 97377424 = 360897^2 + 9868^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-130344022033 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130344021989 and 130344022007.
It is not a weakly prime, because it can be changed into another prime (130344022093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65172011016 + 65172011017.
It is an arithmetic number, because the mean of its divisors is an integer number (65172011017).
Almost surely, 2130344022033 is an apocalyptic number.
It is an amenable number.
130344022033 is a deficient number, since it is larger than the sum of its proper divisors (1).
130344022033 is an equidigital number, since it uses as much as digits as its factorization.
130344022033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 25.
Adding to 130344022033 its reverse (330220443031), we get a palindrome (460564465064).
The spelling of 130344022033 in words is "one hundred thirty billion, three hundred forty-four million, twenty-two thousand, thirty-three".
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