Base | Representation |
---|---|
bin | 11000010001110100… |
… | …10111011110010101 |
3 | 1020122101120010222122 |
4 | 30020322113132111 |
5 | 203143302420432 |
6 | 5553220505325 |
7 | 641001512555 |
oct | 141072273625 |
9 | 36571503878 |
10 | 13034420117 |
11 | 5589654834 |
12 | 263924b245 |
13 | 12c9563834 |
14 | 8b9169165 |
15 | 5144a0612 |
hex | 308e97795 |
13034420117 has 2 divisors, whose sum is σ = 13034420118. Its totient is φ = 13034420116.
The previous prime is 13034420059. The next prime is 13034420129. The reversal of 13034420117 is 71102443031.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10412365681 + 2622054436 = 102041^2 + 51206^2 .
It is a cyclic number.
It is not a de Polignac number, because 13034420117 - 210 = 13034419093 is a prime.
It is a super-2 number, since 2×130344201172 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13034420317) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6517210058 + 6517210059.
It is an arithmetic number, because the mean of its divisors is an integer number (6517210059).
Almost surely, 213034420117 is an apocalyptic number.
It is an amenable number.
13034420117 is a deficient number, since it is larger than the sum of its proper divisors (1).
13034420117 is an equidigital number, since it uses as much as digits as its factorization.
13034420117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 26.
Adding to 13034420117 its reverse (71102443031), we get a palindrome (84136863148).
The spelling of 13034420117 in words is "thirteen billion, thirty-four million, four hundred twenty thousand, one hundred seventeen".
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