Base | Representation |
---|---|
bin | 11000010001110100… |
… | …11100111010111000 |
3 | 1020122101121021120211 |
4 | 30020322130322320 |
5 | 203143304124144 |
6 | 5553221200504 |
7 | 641001634603 |
oct | 141072347270 |
9 | 36571537524 |
10 | 13034442424 |
11 | 558966a573 |
12 | 2639260134 |
13 | 12c9570a33 |
14 | 8b917333a |
15 | 5144a7034 |
hex | 308e9ceb8 |
13034442424 has 128 divisors (see below), whose sum is σ = 26869708800. Its totient is φ = 5911234560.
The previous prime is 13034442409. The next prime is 13034442479. The reversal of 13034442424 is 42424443031.
13034442424 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×130344424243 (a number of 31 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 54537297 + ... + 54537535.
It is an arithmetic number, because the mean of its divisors is an integer number (209919600).
Almost surely, 213034442424 is an apocalyptic number.
It is an amenable number.
13034442424 is an abundant number, since it is smaller than the sum of its proper divisors (13835266376).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13034442424 is a wasteful number, since it uses less digits than its factorization.
13034442424 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 485 (or 481 counting only the distinct ones).
The product of its (nonzero) digits is 36864, while the sum is 31.
Adding to 13034442424 its reverse (42424443031), we get a palindrome (55458885455).
The spelling of 13034442424 in words is "thirteen billion, thirty-four million, four hundred forty-two thousand, four hundred twenty-four".
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