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1303661116543 is a prime number
BaseRepresentation
bin10010111110001000010…
…000011111110001111111
311121121222101101102222011
4102332020100133301333
5132324344221212133
62434521010032051
7163120636440502
oct22761020376177
94547871342864
101303661116543
11462974794245
121907a9578627
1395c1c7557a6
14471518c7139
1523da055a6cd
hex12f8841fc7f

1303661116543 has 2 divisors, whose sum is σ = 1303661116544. Its totient is φ = 1303661116542.

The previous prime is 1303661116517. The next prime is 1303661116573. The reversal of 1303661116543 is 3456111663031.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1303661116543 is a prime.

It is a super-2 number, since 2×13036611165432 (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1303661116496 and 1303661116505.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1303661116573) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 651830558271 + 651830558272.

It is an arithmetic number, because the mean of its divisors is an integer number (651830558272).

Almost surely, 21303661116543 is an apocalyptic number.

1303661116543 is a deficient number, since it is larger than the sum of its proper divisors (1).

1303661116543 is an equidigital number, since it uses as much as digits as its factorization.

1303661116543 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 40.

Adding to 1303661116543 its reverse (3456111663031), we get a palindrome (4759772779574).

The spelling of 1303661116543 in words is "one trillion, three hundred three billion, six hundred sixty-one million, one hundred sixteen thousand, five hundred forty-three".