Base | Representation |
---|---|
bin | 11000010010000111… |
… | …00111001101111111 |
3 | 1020122120010021210111 |
4 | 30021003213031333 |
5 | 203144413001103 |
6 | 5553344450451 |
7 | 641031226156 |
oct | 141103471577 |
9 | 36576107714 |
10 | 13036843903 |
11 | 558aa5a866 |
12 | 263a019a27 |
13 | 12c9c01b25 |
14 | 8b95da59d |
15 | 5147cd86d |
hex | 3090e737f |
13036843903 has 2 divisors, whose sum is σ = 13036843904. Its totient is φ = 13036843902.
The previous prime is 13036843891. The next prime is 13036843909. The reversal of 13036843903 is 30934863031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13036843903 - 25 = 13036843871 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13036843909) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6518421951 + 6518421952.
It is an arithmetic number, because the mean of its divisors is an integer number (6518421952).
Almost surely, 213036843903 is an apocalyptic number.
13036843903 is a deficient number, since it is larger than the sum of its proper divisors (1).
13036843903 is an equidigital number, since it uses as much as digits as its factorization.
13036843903 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 139968, while the sum is 40.
The spelling of 13036843903 in words is "thirteen billion, thirty-six million, eight hundred forty-three thousand, nine hundred three".
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