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13039145583731 is a prime number
BaseRepresentation
bin1011110110111110100110…
…1001000000010001110011
31201011112022110211012222222
42331233221221000101303
53202113132232134411
643422033434151255
72514022116515561
oct275575151002163
951145273735888
1013039145583731
114177963830193
1215670a758252b
13737780a14507
14331152d40a31
151792a11484db
hexbdbe9a40473

13039145583731 has 2 divisors, whose sum is σ = 13039145583732. Its totient is φ = 13039145583730.

The previous prime is 13039145583721. The next prime is 13039145583757. The reversal of 13039145583731 is 13738554193031.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13039145583731 - 210 = 13039145582707 is a prime.

It is a super-2 number, since 2×130391455837312 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13039145583721) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6519572791865 + 6519572791866.

It is an arithmetic number, because the mean of its divisors is an integer number (6519572791866).

Almost surely, 213039145583731 is an apocalyptic number.

13039145583731 is a deficient number, since it is larger than the sum of its proper divisors (1).

13039145583731 is an equidigital number, since it uses as much as digits as its factorization.

13039145583731 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4082400, while the sum is 53.

The spelling of 13039145583731 in words is "thirteen trillion, thirty-nine billion, one hundred forty-five million, five hundred eighty-three thousand, seven hundred thirty-one".