Base | Representation |
---|---|
bin | 111100101110000101… |
… | …1100110101011000001 |
3 | 110110120111021000102122 |
4 | 1321130023212223001 |
5 | 4114022231032422 |
6 | 135523005254025 |
7 | 12264216004214 |
oct | 1713413465301 |
9 | 413514230378 |
10 | 130395564737 |
11 | 50333995839 |
12 | 21331264315 |
13 | c3b0b223c9 |
14 | 644dc3777b |
15 | 35d294cd42 |
hex | 1e5c2e6ac1 |
130395564737 has 2 divisors, whose sum is σ = 130395564738. Its totient is φ = 130395564736.
The previous prime is 130395564731. The next prime is 130395564769. The reversal of 130395564737 is 737465593031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115818383041 + 14577181696 = 340321^2 + 120736^2 .
It is a cyclic number.
It is not a de Polignac number, because 130395564737 - 210 = 130395563713 is a prime.
It is not a weakly prime, because it can be changed into another prime (130395564731) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65197782368 + 65197782369.
It is an arithmetic number, because the mean of its divisors is an integer number (65197782369).
Almost surely, 2130395564737 is an apocalyptic number.
It is an amenable number.
130395564737 is a deficient number, since it is larger than the sum of its proper divisors (1).
130395564737 is an equidigital number, since it uses as much as digits as its factorization.
130395564737 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 7144200, while the sum is 53.
The spelling of 130395564737 in words is "one hundred thirty billion, three hundred ninety-five million, five hundred sixty-four thousand, seven hundred thirty-seven".
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