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13039988306400 = 25325211273379541
BaseRepresentation
bin1011110111000001101111…
…0111101111000111100000
31201011121111012112222011200
42331300123313233013200
53202121344001301100
643422253220441200
72514052031530146
oct275603367570740
951147435488150
1013039988306400
1141782564a1200
1215672a1849200
137378864a5293
143311d2c2b596
1517930010de00
hexbdc1bdef1e0

13039988306400 has 1296 divisors, whose sum is σ = 51464983686480. Its totient is φ = 3103930368000.

The previous prime is 13039988306369. The next prime is 13039988306453. The reversal of 13039988306400 is 460388993031.

13039988306400 is a `hidden beast` number, since 130 + 3 + 99 + 88 + 306 + 40 + 0 = 666.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 215 ways as a sum of consecutive naturals, for example, 24103490130 + ... + 24103490670.

Almost surely, 213039988306400 is an apocalyptic number.

13039988306400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13039988306400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (25732491843240).

13039988306400 is an abundant number, since it is smaller than the sum of its proper divisors (38424995380080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13039988306400 is a wasteful number, since it uses less digits than its factorization.

13039988306400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1041 (or 1014 counting only the distinct ones).

The product of its (nonzero) digits is 3359232, while the sum is 54.

The spelling of 13039988306400 in words is "thirteen trillion, thirty-nine billion, nine hundred eighty-eight million, three hundred six thousand, four hundred".