Base | Representation |
---|---|
bin | 1011110111000001101111… |
… | …0111101111001000010101 |
3 | 1201011121111012112222020122 |
4 | 2331300123313233020111 |
5 | 3202121344001301303 |
6 | 43422253220441325 |
7 | 2514052031530253 |
oct | 275603367571025 |
9 | 51147435488218 |
10 | 13039988306453 |
11 | 41782564a1249 |
12 | 15672a1849245 |
13 | 7378864a5304 |
14 | 3311d2c2b5d3 |
15 | 17930010de38 |
hex | bdc1bdef215 |
13039988306453 has 2 divisors, whose sum is σ = 13039988306454. Its totient is φ = 13039988306452.
The previous prime is 13039988306369. The next prime is 13039988306459. The reversal of 13039988306453 is 35460388993031.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12855824592004 + 184163714449 = 3585502^2 + 429143^2 .
It is a cyclic number.
It is not a de Polignac number, because 13039988306453 - 218 = 13039988044309 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13039988306459) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6519994153226 + 6519994153227.
It is an arithmetic number, because the mean of its divisors is an integer number (6519994153227).
Almost surely, 213039988306453 is an apocalyptic number.
It is an amenable number.
13039988306453 is a deficient number, since it is larger than the sum of its proper divisors (1).
13039988306453 is an equidigital number, since it uses as much as digits as its factorization.
13039988306453 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 50388480, while the sum is 62.
The spelling of 13039988306453 in words is "thirteen trillion, thirty-nine billion, nine hundred eighty-eight million, three hundred six thousand, four hundred fifty-three".
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