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13039988306453 is a prime number
BaseRepresentation
bin1011110111000001101111…
…0111101111001000010101
31201011121111012112222020122
42331300123313233020111
53202121344001301303
643422253220441325
72514052031530253
oct275603367571025
951147435488218
1013039988306453
1141782564a1249
1215672a1849245
137378864a5304
143311d2c2b5d3
1517930010de38
hexbdc1bdef215

13039988306453 has 2 divisors, whose sum is σ = 13039988306454. Its totient is φ = 13039988306452.

The previous prime is 13039988306369. The next prime is 13039988306459. The reversal of 13039988306453 is 35460388993031.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12855824592004 + 184163714449 = 3585502^2 + 429143^2 .

It is a cyclic number.

It is not a de Polignac number, because 13039988306453 - 218 = 13039988044309 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13039988306459) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6519994153226 + 6519994153227.

It is an arithmetic number, because the mean of its divisors is an integer number (6519994153227).

Almost surely, 213039988306453 is an apocalyptic number.

It is an amenable number.

13039988306453 is a deficient number, since it is larger than the sum of its proper divisors (1).

13039988306453 is an equidigital number, since it uses as much as digits as its factorization.

13039988306453 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 50388480, while the sum is 62.

The spelling of 13039988306453 in words is "thirteen trillion, thirty-nine billion, nine hundred eighty-eight million, three hundred six thousand, four hundred fifty-three".