Base | Representation |
---|---|
bin | 1011110111000001110111… |
… | …1101010110100100000011 |
3 | 1201011121120122110111210201 |
4 | 2331300131331112210003 |
5 | 3202121431433124443 |
6 | 43422300511310031 |
7 | 2514052635332653 |
oct | 275603575264403 |
9 | 51147518414721 |
10 | 13040023333123 |
11 | 4178274245306 |
12 | 15672b151b317 |
13 | 73789081a257 |
14 | 3311d7748363 |
15 | 17930322c34d |
hex | bdc1df56903 |
13040023333123 has 2 divisors, whose sum is σ = 13040023333124. Its totient is φ = 13040023333122.
The previous prime is 13040023333121. The next prime is 13040023333189. The reversal of 13040023333123 is 32133332004031.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13040023333123 - 21 = 13040023333121 is a prime.
Together with 13040023333121, it forms a pair of twin primes.
It is a junction number, because it is equal to n+sod(n) for n = 13040023333091 and 13040023333100.
It is not a weakly prime, because it can be changed into another prime (13040023333121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520011666561 + 6520011666562.
It is an arithmetic number, because the mean of its divisors is an integer number (6520011666562).
Almost surely, 213040023333123 is an apocalyptic number.
13040023333123 is a deficient number, since it is larger than the sum of its proper divisors (1).
13040023333123 is an equidigital number, since it uses as much as digits as its factorization.
13040023333123 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11664, while the sum is 28.
Adding to 13040023333123 its reverse (32133332004031), we get a palindrome (45173355337154).
The spelling of 13040023333123 in words is "thirteen trillion, forty billion, twenty-three million, three hundred thirty-three thousand, one hundred twenty-three".
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