Base | Representation |
---|---|
bin | 11000010010011111… |
… | …10011100000111111 |
3 | 1020122210010200000102 |
4 | 30021033303200333 |
5 | 203201222234444 |
6 | 5553541151315 |
7 | 641100340220 |
oct | 141117634077 |
9 | 36583120012 |
10 | 13040039999 |
11 | 5591843068 |
12 | 263b0bb53b |
13 | 12ca7807cc |
14 | 8b9bcd247 |
15 | 514c1084e |
hex | 3093f383f |
13040039999 has 4 divisors (see below), whose sum is σ = 14902902864. Its totient is φ = 11177177136.
The previous prime is 13040039989. The next prime is 13040040011. The reversal of 13040039999 is 99993004031.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13040039999 - 24 = 13040039983 is a prime.
It is a super-3 number, since 3×130400399993 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13040039989) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 931431422 + ... + 931431435.
It is an arithmetic number, because the mean of its divisors is an integer number (3725725716).
Almost surely, 213040039999 is an apocalyptic number.
13040039999 is a deficient number, since it is larger than the sum of its proper divisors (1862862865).
13040039999 is an equidigital number, since it uses as much as digits as its factorization.
13040039999 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1862862864.
The product of its (nonzero) digits is 236196, while the sum is 47.
The spelling of 13040039999 in words is "thirteen billion, forty million, thirty-nine thousand, nine hundred ninety-nine".
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