13040040011 has 2 divisors, whose sum is σ = 13040040012. Its totient is φ = 13040040010.

The previous prime is 13040039989. The next prime is 13040040017. The reversal of 13040040011 is 11004004031.

It is a happy number.

13040040011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (11004004031) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13040040011 is a prime.

It is not a weakly prime, because it can be changed into another prime (13040040017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6520020005 + 6520020006.

It is an arithmetic number, because the mean of its divisors is an integer number (6520020006).

Almost surely, 2^13040040011 is an apocalyptic number.

13040040011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13040040011 is an equidigital number, since it uses as much as digits as its factorization.

13040040011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 13040040011 its reverse (11004004031), we get a palindrome (24044044042).

The spelling of 13040040011 in words is "thirteen billion, forty million, forty thousand, eleven".