Base | Representation |
---|---|
bin | 111100101110001111… |
… | …0001100111101000101 |
3 | 110110120211102201012212 |
4 | 1321130132030331011 |
5 | 4114030003041013 |
6 | 135523301553205 |
7 | 12264305311205 |
oct | 1713436147505 |
9 | 413524381185 |
10 | 130400440133 |
11 | 50336715797 |
12 | 21332a15805 |
13 | c3b1b3b562 |
14 | 6450746405 |
15 | 35d30b26a8 |
hex | 1e5c78cf45 |
130400440133 has 2 divisors, whose sum is σ = 130400440134. Its totient is φ = 130400440132.
The previous prime is 130400440097. The next prime is 130400440171. The reversal of 130400440133 is 331044004031.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107290967809 + 23109472324 = 327553^2 + 152018^2 .
It is a cyclic number.
It is not a de Polignac number, because 130400440133 - 210 = 130400439109 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 130400440099 and 130400440108.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130400440733) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200220066 + 65200220067.
It is an arithmetic number, because the mean of its divisors is an integer number (65200220067).
Almost surely, 2130400440133 is an apocalyptic number.
It is an amenable number.
130400440133 is a deficient number, since it is larger than the sum of its proper divisors (1).
130400440133 is an equidigital number, since it uses as much as digits as its factorization.
130400440133 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 130400440133 its reverse (331044004031), we get a palindrome (461444444164).
The spelling of 130400440133 in words is "one hundred thirty billion, four hundred million, four hundred forty thousand, one hundred thirty-three".
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