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130400440133 is a prime number
BaseRepresentation
bin111100101110001111…
…0001100111101000101
3110110120211102201012212
41321130132030331011
54114030003041013
6135523301553205
712264305311205
oct1713436147505
9413524381185
10130400440133
1150336715797
1221332a15805
13c3b1b3b562
146450746405
1535d30b26a8
hex1e5c78cf45

130400440133 has 2 divisors, whose sum is σ = 130400440134. Its totient is φ = 130400440132.

The previous prime is 130400440097. The next prime is 130400440171. The reversal of 130400440133 is 331044004031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 107290967809 + 23109472324 = 327553^2 + 152018^2 .

It is a cyclic number.

It is not a de Polignac number, because 130400440133 - 210 = 130400439109 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 130400440099 and 130400440108.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130400440733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65200220066 + 65200220067.

It is an arithmetic number, because the mean of its divisors is an integer number (65200220067).

Almost surely, 2130400440133 is an apocalyptic number.

It is an amenable number.

130400440133 is a deficient number, since it is larger than the sum of its proper divisors (1).

130400440133 is an equidigital number, since it uses as much as digits as its factorization.

130400440133 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 130400440133 its reverse (331044004031), we get a palindrome (461444444164).

The spelling of 130400440133 in words is "one hundred thirty billion, four hundred million, four hundred forty thousand, one hundred thirty-three".