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13040104030 = 251606381181
BaseRepresentation
bin11000010010100000…
…00011001001011110
31020122210020220211221
430021100003021132
5203201231312110
65553542403554
7641101025002
oct141120031136
936583226757
1013040104030
115591887188
12263b1305ba
1312ca7a39b5
148b9c08702
15514c247da
hex30940325e

13040104030 has 16 divisors (see below), whose sum is σ = 23473937664. Its totient is φ = 5215652640.

The previous prime is 13040104009. The next prime is 13040104057. The reversal of 13040104030 is 3040104031.

It is a super-2 number, since 2×130401040302 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13040103995 and 13040104013.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 120040 + ... + 201220.

It is an arithmetic number, because the mean of its divisors is an integer number (1467121104).

Almost surely, 213040104030 is an apocalyptic number.

13040104030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13040104030 is a deficient number, since it is larger than the sum of its proper divisors (10433833634).

13040104030 is a wasteful number, since it uses less digits than its factorization.

13040104030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 97251.

The product of its (nonzero) digits is 144, while the sum is 16.

Adding to 13040104030 its reverse (3040104031), we get a palindrome (16080208061).

Subtracting from 13040104030 its reverse (3040104031), we obtain a palindrome (9999999999).

The spelling of 13040104030 in words is "thirteen billion, forty million, one hundred four thousand, thirty".

Divisors: 1 2 5 10 16063 32126 80315 81181 160630 162362 405905 811810 1304010403 2608020806 6520052015 13040104030